Find x
in Ax = b
. If b
not supplied,
the inverse of A
is returned.
solve_lin(A, b)
matrix
vector
if (has_sympy()) {
A <- matrix_sym(2, 2, "a")
b <- vector_sym(2, "b")
# Inverse of A:
solve_lin(A) %*% A |> simplify()
# Find x in Ax = b
x <- solve_lin(A, b)
A %*% x |> simplify()
}
#> c: [b₁ b₂]ᵀ